报告不必要的原本有更简单的替代方案的复杂集合操作。

示例:


  void f(String[] array, Collection<String> collection) {
    String[] strings = Arrays.asList(array).subList(0, 10).toArray(new String[0]);
    boolean contains = collection.containsAll(Collections.singletonList("x"));
  }

在应用快速修复后:


  void f(String[] array, Collection<String> collection) {
    String[] strings = Arrays.copyOf(array, 10);
    boolean contains = collection.contains("x");
  }

2018.1 的新功能